Two trolleys of mass m and 3m are connected by a spring. They were compressed and released once, they move off in opposite direction and comes to rest after covering distances S_1 and S_{2} respectively. Assuming the coefficient of friction to be uniform, the ratio of distances S_{1} : S_{2} is
Text Solution
Verified by ExpertsD
When trolley are released then they posses same linear momentum but in opposite direction. Kinetic energy acquired by any trolley will dissipate against friction.
\(\cdot\) \(\mu mg s = \frac{p^{2}}{2m}\) ⇒ ⇒ \(S \propto \frac{1}{m}\) [As P and u are constants]
⇒ ⇒ \(\frac{s_1}{s_2} = \left(\frac{m_1}{m_2}\right)^2 = \left(\frac{3}{1}\right)^2 = \frac{9}{1}\)
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems